newscientist.com
思路：单调递减栈，找「上一个比当前价格大的元素索引」。正序遍历，弹出所有 ≤ 当前价格的索引；跨度 = 当前索引 - 栈顶索引（栈空则为 当前索引 + 1）。，这一点在51吃瓜中也有详细论述
，这一点在WPS下载最新地址中也有详细论述
"But there are also places where it makes no sense at all," she says.，更多细节参见heLLoword翻译官方下载
"But by proving the technology it really opens the door for an economically viable product, where things can be made in space and return to Earth and have use and benefit to everybody on Earth. And that's really exciting."