思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
// Synchronous consumption — no promises, no event loop trips
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"The gaming landscape is struggling to find its footing faced with competition from insta-gratification platforms like Instagram, and TikTok," he told the BBC.
，更多细节参见搜狗输入法下载
@OptIn(ExperimentalForeignApi::class)
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